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(B) The total number of cards in a pack is $52$. The probability of drawing a queen of clubs is $P(A) = \frac{1}{52}$. The probability of drawing a ki

Vedclass · Accepted Answer

$\frac{1}{26}$

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(B) The total number of cards in a pack is $52$. The probability of drawing a queen of clubs is $P(A) = \frac{1}{52}$. The probability of drawing a king of hearts is $P(B) = \frac{1}{52}$. Since these are mutually exclusive events,the probability of getting a queen of clubs or a king of hearts is $P(A \cup B) = P(A) + P(B)$. Therefore,the required probability is $\frac{1}{52} + \frac{1}{52} = \frac{2}{52} = \frac{1}{26}$.

$A$ card is drawn from a well-shuffled pack of $52$ cards. The probability of getting a queen of clubs or a king of hearts is

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