$A$ certain particle carries $2.5 \times 10^{-16} \, C$ of static electric charge. Calculate the number of electrons present in it.

(N/A) The charge on one electron is $e = 1.6022 \times 10^{-19} \, C$.
According to the quantization of charge,the total charge $q$ is given by $q = n \times e$,where $n$ is the number of electrons.
Therefore,$n = \frac{q}{e}$.
Substituting the given values:
$n = \frac{2.5 \times 10^{-16} \, C}{1.6022 \times 10^{-19} \, C} \approx 1560.35$.
Since the number of electrons must be an integer,the number of electrons present is $1560$.