A charge of 10 ,mu C is placed at the origin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The electric potential $V$ at a distance $r$ from a point charge $q$ is given by $V = \frac{kq}{r}$,where $k = 9 	imes 10^9 \, N \cdot m^2/C^2$.F

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) The electric potential $V$ at a distance $r$ from a point charge $q$ is given by $V = \frac{kq}{r}$,where $k = 9 	imes 10^9 \, N \cdot m^2/C^2$.For point $A(0, a)$,the distance from the origin is $r_A = \sqrt{0^2 + a^2} = a$.Thus,the potential at $A$ is $V_A = \frac{kq}{a}$.For point $B(a, 0)$,the distance from the origin is $r_B = \sqrt{a^2 + 0^2} = a$.Thus,the potential at $B$ is $V_B = \frac{kq}{a}$.The potential difference between points $A$ and $B$ is $\Delta V = V_A - V_B = \frac{kq}{a} - \frac{kq}{a} = 0$.

$A$ charge of $10 \,\mu C$ is placed at the origin of an $x-y$ coordinate system. The potential difference between two points $(0, a)$ and $(a, 0)$ in volts will be

Similar Questions

Two concentric hollow conducting spheres of radius $r$ and $R$ $(r < R)$ are shown. The charge on the outer shell is $Q$. What charge $q$ should be given to the inner sphere so that the potential at any point $P$ at a distance $x$ $(x > R)$ from the center is zero?

An electron of charge $e$ coulomb passes through a potential difference of $V$ volts. Its energy in joules will be

$A$ positively charged ring is in the $y-z$ plane with its centre at the origin. $A$ positive test charge $q_0$,held at the origin,is released along the $x$-axis. Then its speed

Inside a hollow charged spherical conductor,the potential

$A$ hollow conducting sphere of radius $R$ carries a charge $(+Q)$ on its surface. Find the electric potential at a distance $r = R/3$ from its center.

Vedclass Test Series

Exam Paper Generator

Online Exam Module