A charged particle is suspended in equilibriu | vedclass

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Question

(A) For a charged particle to be in equilibrium in a vertical electric field,the upward electric force must balance the downward gravitational force.$

Vedclass · Accepted Answer

$4.8 	imes 10^{-19}\, C, 3$

Vedclass · Answer

(A) For a charged particle to be in equilibrium in a vertical electric field,the upward electric force must balance the downward gravitational force.$F_e = F_g$$qE = mg$$q = \frac{mg}{E} = \frac{9.6 	imes 10^{-16} 	imes 10}{20,000} = \frac{9.6 	imes 10^{-15}}{2 	imes 10^4} = 4.8 	imes 10^{-19}\, C$.Since $q = ne$,the number of excess electrons $n$ is:$n = \frac{q}{e} = \frac{4.8 	imes 10^{-19}}{1.6 	imes 10^{-19}} = 3$.Thus,the charge is $4.8 	imes 10^{-19}\, C$ and the number of electrons is $3$.

$A$ charged particle is suspended in equilibrium in a uniform vertical electric field of intensity $20,000\, V/m$. If the mass of the particle is $9.6 \times 10^{-16}\, kg$,the charge on it and the excess number of electrons on the particle are respectively $(g = 10\, m/s^2)$.

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