A circle and a rectangle have the same perime | vedclass

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(D) The perimeter of the rectangle is $P = 2(l + b) = 2(18 + 26) = 2(44) = 88 	ext{ cm}$.Since the perimeter of the circle is equal to the perimeter

Vedclass · Accepted Answer

$616$

Vedclass · Answer

(D) The perimeter of the rectangle is $P = 2(l + b) = 2(18 + 26) = 2(44) = 88 	ext{ cm}$.Since the perimeter of the circle is equal to the perimeter of the rectangle,we have $2 \pi r = 88 	ext{ cm}$.Substituting $\pi = \frac{22}{7}$,we get $2 	imes \frac{22}{7} 	imes r = 88$.$\frac{44}{7} 	imes r = 88 \Rightarrow r = 88 	imes \frac{7}{44} = 14 	ext{ cm}$.The area of the circle is $A = \pi r^2 = \frac{22}{7} 	imes 14 	imes 14$.$A = 22 	imes 2 	imes 14 = 616 	ext{ cm}^2$.

$A$ circle and a rectangle have the same perimeter. The sides of the rectangle are $18 \text{ cm}$ and $26 \text{ cm}$. The area of the circle is .......... $\text{cm}^2$. [Take $\pi = \frac{22}{7}$]

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