A circular coil of radius R and N turns has n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The torque $	au$ experienced by a current-carrying coil in a magnetic field is given by $\vec{	au} = \vec{M} 	imes \vec{B}_0$,where $\vec{M}$ i

Vedclass · Accepted Answer

$\pi N Q B_0 R^2$

Vedclass · Answer

(B) The torque $	au$ experienced by a current-carrying coil in a magnetic field is given by $\vec{	au} = \vec{M} 	imes \vec{B}_0$,where $\vec{M}$ is the magnetic moment of the coil.The magnitude of the torque is $	au = M B_0 \sin(	heta)$. Since the plane of the coil is vertical and the magnetic field $B_0$ is horizontal and parallel to the plane of the coil,the angle between the area vector (normal to the plane) and the magnetic field is $	heta = 90^\circ$. Thus,$\sin(90^\circ) = 1$.The magnetic moment of the coil is $M = N i A = N i (\pi R^2)$.Therefore,the torque is $	au = N i \pi R^2 B_0$.From the angular impulse-momentum theorem,the change in angular momentum $L$ is given by $\Delta L = \int 	au dt$.Substituting the expression for torque: $\Delta L = \int (N i \pi R^2 B_0) dt = N \pi R^2 B_0 \int i dt$.Since the total charge $Q$ discharged through the coil is $Q = \int i dt$,we get:$L = N \pi R^2 B_0 Q$.

Similar Questions

$A$ metal wire of length '$L$' is bent to form a circular coil of number of turns '$n$'. The coil is placed in a magnetic field '$B$' and a current '$I$' is passed through the coil. The maximum torque acting on the coil is:

$A$ wire of length $L$ is bent in the form of a circular coil and current $i$ is passed through it. This coil is kept in a magnetic field. The torque acting on the coil will be maximum, when the number of turns is . . . . . .

$A$ conducting ring of mass $2 \ kg$ and radius $0.5 \ m$ is placed on a smooth horizontal plane. The ring carries a current $i = 4 \ A$. $A$ horizontal magnetic field $B = 10 \ T$ is switched on at time $t = 0$ as shown in the figure. The initial angular acceleration of the ring will be:

$A$ circular coil carrying a current of $2.5 \ A$ is free to rotate about an axis in its plane perpendicular to an external magnetic field. When the coil is made to oscillate, the time period of oscillation is $T$. If the current through the coil is $10 \ A$, the time period of oscillation is

Vedclass Test Series

Exam Paper Generator

Online Exam Module