A circular coil of radius 4, cm and of 20 tur | vedclass

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(B) The magnetic dipole moment $M$ of a coil is given by the formula $M = N \cdot i \cdot A$,where $N$ is the number of turns,$i$ is the current,and $

Vedclass · Accepted Answer

$0.3$

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(B) The magnetic dipole moment $M$ of a coil is given by the formula $M = N \cdot i \cdot A$,where $N$ is the number of turns,$i$ is the current,and $A$ is the area of the coil.Given:$N = 20$$i = 3\, A$$r = 4\, cm = 4 	imes 10^{-2}\, m$Area $A = \pi r^2 = \pi 	imes (4 	imes 10^{-2})^2 = 16\pi 	imes 10^{-4}\, m^2$.Using $\pi \approx 3.14$:$A \approx 3.14 	imes 16 	imes 10^{-4} = 50.24 	imes 10^{-4}\, m^2$.Now,$M = 20 	imes 3 	imes 50.24 	imes 10^{-4} = 60 	imes 50.24 	imes 10^{-4} = 3014.4 	imes 10^{-4} \approx 0.3\, A \cdot m^2$.Thus,the correct option is $B$.

$A$ circular coil of radius $4\, cm$ and of $20$ turns carries a current of $3$ amperes. It is placed in a magnetic field of intensity $0.5\, Wb/m^2$. The magnetic dipole moment of the coil is.......$A \cdot m^2$.

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