A clock has a continuously moving second's ha | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The length of the second's hand is the radius of the circular path,$R = 0.1\, m$.The time period for the second's hand is $T = 60\, s$.The angular

Vedclass · Accepted Answer

$10^{-3}$

Vedclass · Answer

(A) The length of the second's hand is the radius of the circular path,$R = 0.1\, m$.The time period for the second's hand is $T = 60\, s$.The angular velocity $\omega$ is given by $\omega = \frac{2\pi}{T} = \frac{2\pi}{60} \approx 0.105\, rad/s$.The centripetal acceleration $a$ of the tip of the hand is given by $a = \omega^2 R$.Substituting the values: $a = (0.105)^2 	imes 0.1$.$a \approx 0.011025 	imes 0.1 = 0.0011025\, m/s^2$.This can be written as $1.1 	imes 10^{-3}\, m/s^2$.Therefore,the average acceleration is of the order of $10^{-3}$.

$A$ clock has a continuously moving second's hand of $0.1\, m$ length. The average acceleration of the tip of the hand (in units of $m\, s^{-2}$) is of the order of

Similar Questions

$A$ car wheel is rotating at $1200$ revolutions per minute. On pressing the accelerator,it reaches $4500$ revolutions per minute in $10 \, s$. The angular acceleration of the wheel is:

Angular displacement $(\theta)$ of a flywheel varies with time as $\theta = at + bt^2 + ct^3$. The angular acceleration is given by:

$A$ disc starts from rest and acquires an angular velocity of $240 \ rpm$ in $10 \ s$. The angular acceleration is ...... $rad/s^2$ (assuming it is constant).

The angular speed of a wheel increases from $600 \, rpm$ to $1200 \, rpm$ in $10 \, s$. What is the angular acceleration?

$A$ wheel is rotating at $900 \, r.p.m.$ about its axis. When the power is cut-off,it comes to rest in $1 \, minute$. The angular retardation in $rad/s^2$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module