A coil of area 80, cm^2 and 50, turns is rota | vedclass

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(C) The maximum $emf$ $(E_{\max})$ induced in a rotating coil is given by the formula: $E_{\max} = N A B \omega$.Here,$N = 50$ (number of turns),$A =

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$\frac{4\pi}{3} \, V$

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(C) The maximum $emf$ $(E_{\max})$ induced in a rotating coil is given by the formula: $E_{\max} = N A B \omega$.Here,$N = 50$ (number of turns),$A = 80 \, cm^2 = 80 	imes 10^{-4} \, m^2 = 8 	imes 10^{-3} \, m^2$,$B = 0.05 \, T$,and the angular frequency $\omega = 2\pi f$.The frequency $f = \frac{2000}{60} \, Hz = \frac{100}{3} \, Hz$.Thus,$\omega = 2\pi 	imes \frac{100}{3} = \frac{200\pi}{3} \, rad/s$.Substituting these values into the formula:$E_{\max} = 50 	imes (8 	imes 10^{-3}) 	imes 0.05 	imes \frac{200\pi}{3}$$E_{\max} = 50 	imes 0.008 	imes 0.05 	imes \frac{200\pi}{3}$$E_{\max} = 0.4 	imes 0.05 	imes \frac{200\pi}{3} = 0.02 	imes \frac{200\pi}{3} = \frac{4\pi}{3} \, V$.

$A$ coil of area $80\, cm^2$ and $50\, turns$ is rotating with $2000$ revolutions per minute about an axis perpendicular to a magnetic field of $0.05\, T$. The maximum value of the $emf$ developed in it is

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