$A$ coin is tossed twice. If events $A$ and $B$ are defined as: $A = \text{head on first toss}$,$B = \text{head on second toss}$. Then the probability of $A \cup B = $

  • A
    $\frac{1}{4}$
  • B
    $\frac{1}{2}$
  • C
    $\frac{1}{8}$
  • D
    $\frac{3}{4}$

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