A coin is tossed two times. Find the probabil | vedclass

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(A) The possible outcomes when a coin is tossed $2$ times are:$S = \{(H, H), (H, T), (T, H), (T, T)\}$Therefore,the total number of outcomes $n(S) = 4

Vedclass · Accepted Answer

$\frac{3}{4}$

Vedclass · Answer

(A) The possible outcomes when a coin is tossed $2$ times are:$S = \{(H, H), (H, T), (T, H), (T, T)\}$Therefore,the total number of outcomes $n(S) = 4$.Let $E$ be the event of getting at most one head.This means getting zero heads or one head.The outcomes favorable to event $E$ are $\{(T, T), (H, T), (T, H)\}$.Therefore,the number of favorable outcomes $n(E) = 3$.The probability of the event $E$ is given by $P(E) = \frac{n(E)}{n(S)}$.Thus,$P(E) = \frac{3}{4}$.

$A$ coin is tossed two times. Find the probability of getting at most one head.

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