A colour-blind man marries a woman with norma | vedclass

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(B) $1$. The colour-blind man has the genotype $X^cY$ and the normal woman has the genotype $XX$.$2$. Their offspring will be: $X^cX$ (carrier daughte

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$0.25$

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(B) $1$. The colour-blind man has the genotype $X^cY$ and the normal woman has the genotype $XX$.$2$. Their offspring will be: $X^cX$ (carrier daughters) and $XY$ (normal sons).$3$. The grandsons are the children of the $F_1$ generation. The $F_1$ sons $(XY)$ will have children with a normal woman $(XX)$, resulting in all normal children (no colour-blind grandsons from this lineage).$4$. The $F_1$ carrier daughters $(X^cX)$ will have children with a normal man $(XY)$. The possible genotypes for their children are: $XX$ (normal daughter), $X^cX$ (carrier daughter), $XY$ (normal son), and $X^cY$ (colour-blind son).$5$. The probability of a grandson being colour-blind is the probability that the daughter is a carrier $(1)$ multiplied by the probability that she has a colour-blind son $(1/4)$, which equals $1/4$ or $0.25$.

$A$ colour-blind man marries a woman with normal sight who has no history of colour blindness in her family. What is the probability of their grandson being colour-blind?

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