A compound M_pX_q has a cubic close packing ( | vedclass

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(B) In the given unit cell,$X$ atoms are at the corners and face centers,which is characteristic of a $ccp$ arrangement.Number of $X$ atoms = $8 	ime

Vedclass · Accepted Answer

$MX_2$

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(B) In the given unit cell,$X$ atoms are at the corners and face centers,which is characteristic of a $ccp$ arrangement.Number of $X$ atoms = $8 	imes \frac{1}{8} (	ext{corners}) + 6 	imes \frac{1}{2} (	ext{face centers}) = 1 + 3 = 4$.$M$ atoms are located at the edges (specifically,there are $4$ $M$ atoms on the edges,each shared by $4$ unit cells) and one at the body center.Number of $M$ atoms = $4 	imes \frac{1}{4} (	ext{edges}) + 1 (	ext{body center}) = 1 + 1 = 2$.The ratio of $M:X$ is $2:4$,which simplifies to $1:2$.Therefore,the empirical formula is $MX_2$.

$A$ compound $M_pX_q$ has a cubic close packing $(ccp)$ arrangement of $X$. Its unit cell structure is shown below. The empirical formula of the compound is:
$M = \square$
$X = \bigcirc$

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$A$ compound $M_pX_q$ has a cubic close packing $(ccp)$ arrangement of $X$. Its unit cell structure is shown below. The empirical formula of the compound is:$M = \square$$X = \bigcirc$