A compound Z with molecular formula C_3H_9N r | vedclass

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(C) The reaction of an amine with $C_6H_5SO_2Cl$ (Hinsberg reagent) is used to distinguish between primary,secondary,and tertiary amines.Primary amine

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$CH_3NHC_2H_5$

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(C) The reaction of an amine with $C_6H_5SO_2Cl$ (Hinsberg reagent) is used to distinguish between primary,secondary,and tertiary amines.Primary amines $(RNH_2)$ react to form a sulfonamide that is soluble in alkali due to the acidic hydrogen on the nitrogen atom.Secondary amines $(R_2NH)$ react to form a sulfonamide that is insoluble in alkali because there is no acidic hydrogen on the nitrogen atom.Tertiary amines $(R_3N)$ do not react with $C_6H_5SO_2Cl$.Since the product is a solid insoluble in alkali,$Z$ must be a secondary amine.Given the molecular formula $C_3H_9N$,the secondary amine is ethylmethylamine $(CH_3NHC_2H_5)$.The reaction is: $CH_3NHC_2H_5 + C_6H_5SO_2Cl \rightarrow C_6H_5SO_2N(CH_3)C_2H_5 + HCl$.

$A$ compound $Z$ with molecular formula $C_3H_9N$ reacts with $C_6H_5SO_2Cl$ to give a solid,insoluble in alkali. Identify $Z$.

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