A compound M_pX_q has a cubic close packing ( | vedclass

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(B) In the given unit cell,$X$ atoms are at the corners and face centers (typical $ccp$ arrangement).Number of $X$ atoms $= (8 	ext{ corners} 	imes

Vedclass · Accepted Answer

$MX_2$

Vedclass · Answer

(B) In the given unit cell,$X$ atoms are at the corners and face centers (typical $ccp$ arrangement).Number of $X$ atoms $= (8 	ext{ corners} 	imes \frac{1}{8}) + (6 	ext{ face centers} 	imes \frac{1}{2}) = 1 + 3 = 4$.$M$ atoms are located at the edges and the body center.Number of $M$ atoms $= (4 	ext{ edges} 	imes \frac{1}{4}) + (1 	ext{ body center} 	imes 1) = 1 + 1 = 2$.Ratio of $M:X = 2:4 = 1:2$.Therefore,the empirical formula is $MX_2$.

$A$ compound $M_pX_q$ has a cubic close packing $(ccp)$ arrangement of $X$. Its unit cell structure is shown below. The empirical formula of the compound is

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