A compound contains atoms X,Y,and Z. The oxid | vedclass

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(C) The net charge on the compound must be zero,meaning the sum of the oxidation states of all atoms must be $0$.Given: Oxidation number of $X = +2$,$

Vedclass · Accepted Answer

$X_3(YZ_4)_2$

Vedclass · Answer

(C) The net charge on the compound must be zero,meaning the sum of the oxidation states of all atoms must be $0$.Given: Oxidation number of $X = +2$,$Y = +5$,and $Z = -2$.Let us check each option:$A) XYZ_2: (+2) + (+5) + 2 	imes (-2) = 2 + 5 - 4 = +3 
eq 0$$B) X_2(YZ_3)_2: 2 	imes (+2) + 2 	imes (5 + 3 	imes (-2)) = 4 + 2 	imes (5 - 6) = 4 - 2 = +2 
eq 0$$C) X_3(YZ_4)_2: 3 	imes (+2) + 2 	imes (5 + 4 	imes (-2)) = 6 + 2 	imes (5 - 8) = 6 + 2 	imes (-3) = 6 - 6 = 0$$D) X_3(Y_4Z)_2: 3 	imes (+2) + 2 	imes (4 	imes 5 - 2) = 6 + 2 	imes (18) = 42 
eq 0$Thus,the correct formula is $X_3(YZ_4)_2$.

$A$ compound contains atoms $X$,$Y$,and $Z$. The oxidation number of $X$ is $+2$,$Y$ is $+5$ and $Z$ is $-2$. Therefore,a possible formula of the compound is

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