A compound contains three elements A,B,and C. | vedclass

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(B) The sum of oxidation numbers of all atoms in a neutral molecule must be zero.For $A_3(B_4C)_2$: $(+2 	imes 3) + 2 	imes [(+5 	imes 4) + (-2)] =

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$A_3(BC_4)_2$

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(B) The sum of oxidation numbers of all atoms in a neutral molecule must be zero.For $A_3(B_4C)_2$: $(+2 	imes 3) + 2 	imes [(+5 	imes 4) + (-2)] = 6 + 36 = 42 
eq 0$.For $A_3(BC_4)_2$: $(+2 	imes 3) + 2 	imes [(+5) + (-2 	imes 4)] = 6 + 2 	imes (-3) = 6 - 6 = 0$.For $A_2(BC_3)_2$: $(+2 	imes 2) + 2 	imes [(+5) + (-2 	imes 3)] = 4 + 2 	imes (-1) = 2 
eq 0$.For $ABC_2$: $(+2) + (+5) + (-2 	imes 2) = 7 - 4 = 3 
eq 0$.Thus,the correct formula is $A_3(BC_4)_2$.

$A$ compound contains three elements $A$,$B$,and $C$. If the oxidation numbers are $A = +2$,$B = +5$,and $C = -2$,the possible formula of the compound is:

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