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(C) The actual depth of the water is $d = 33.25 \, cm$. The refractive index of water is $\mu = 1.33 = 4/3$.The apparent depth of the object from the

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$20$

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(C) The actual depth of the water is $d = 33.25 \, cm$. The refractive index of water is $\mu = 1.33 = 4/3$.The apparent depth of the object from the water surface is $d' = d / \mu = 33.25 / (4/3) = 33.25 	imes 0.75 = 24.9375 \, cm \approx 25 \, cm$.The mirror is placed $15 \, cm$ above the water surface.Therefore,the total distance of the object from the mirror is $u = 15 \, cm + 25 \, cm = 40 \, cm$.Since the image is formed at the same position as the object (as implied by the setup where the object is at the center of curvature for a concave mirror to form an image at the same point),the object distance $u$ is equal to the radius of curvature $R$.Thus,$R = 40 \, cm$.The focal length $f$ is given by $f = R / 2 = 40 / 2 = 20 \, cm$.

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