A concave mirror of focal length f produces a | vedclass

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(C) For a concave mirror,the magnification $m$ is given by the formula $m = \frac{f}{f-u}$,where $f$ is the focal length and $u$ is the object distanc

Vedclass · Accepted Answer

$\left(\frac{n+1}{n}\right) f$

Vedclass · Answer

(C) For a concave mirror,the magnification $m$ is given by the formula $m = \frac{f}{f-u}$,where $f$ is the focal length and $u$ is the object distance.Since the image is real,the magnification $m$ must be negative. Given that the image size is $n$ times the object size,we have $m = -n$.Substituting this into the formula: $-n = \frac{-f}{-f-u}$.Multiplying both sides by $(-f-u)$,we get: $-n(-f-u) = -f$.$nf + nu = -f$.$nu = -f - nf$.$nu = -f(n+1)$.$u = -\frac{f(n+1)}{n}$.The distance of the object from the mirror is the magnitude of $u$,which is $|u| = \left(\frac{n+1}{n}\right) f$.

$A$ concave mirror of focal length $f$ produces an image $n$ times the size of the object. If the image is real,then the distance of the object from the mirror is:

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