A condenser having a capacity of 6,mu F is ch | vedclass

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(C) Initial charge on the $6\,\mu F$ capacitor is $Q = C_1 V_0 = 6\,\mu F 	imes 100\,V = 600\,\mu C$.When connected in parallel,the capacitors share

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$6/14$ and $30\,V$

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(C) Initial charge on the $6\,\mu F$ capacitor is $Q = C_1 V_0 = 6\,\mu F 	imes 100\,V = 600\,\mu C$.When connected in parallel,the capacitors share charge until they reach a common potential $V$.The common potential $V$ is given by $V = \frac{Q_{total}}{C_1 + C_2} = \frac{600\,\mu C}{6\,\mu F + 14\,\mu F} = \frac{600}{20} = 30\,V$.The charges on the capacitors are $q_1 = C_1 V = 6\,\mu F 	imes 30\,V = 180\,\mu C$ and $q_2 = C_2 V = 14\,\mu F 	imes 30\,V = 420\,\mu C$.The ratio of the charges is $\frac{q_1}{q_2} = \frac{C_1}{C_2} = \frac{6}{14}$.Thus,the ratio is $6/14$ and the potential is $30\,V$.

$A$ condenser having a capacity of $6\,\mu F$ is charged to $100\, V$ and is then joined to an uncharged condenser of $14\,\mu F$ and then removed. The ratio of the charges on $6\,\mu F$ and $14\,\mu F$ and the potential of $6\,\mu F$ will be

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