$A$ conducting rod of length $l$ is falling with a velocity $v$ perpendicular to a uniform horizontal magnetic field $B$. The potential difference between its two ends will be

$A$ $1 \ m$ long metal rod $AB$ completes the circuit as shown in the figure. The area of the circuit is perpendicular to the magnetic field of $0.10 \ T$. If the resistance of the total circuit is $2 \ \Omega$, then the force needed to move the rod towards the right with a constant speed $(v)$ of $1.5 \ m/s$ is . . . . . . $N$.

$A$ conducting rod $AB$ moves parallel to the $X-$ axis in a uniform magnetic field,which is directed perpendicular to the plane of motion (outwards). The end $A$ of the rod gets:

The migratory pattern of birds is one of the mysteries in the field of biology and indeed all of science. Explain this in the context of electromagnetic induction.

$A$ rectangular,a square,a circular,and an elliptical loop,all in the $(x-y)$ plane,are moving out of a uniform magnetic field with a constant velocity,$\vec{V} = v\hat{i}$. The magnetic field is directed along the negative $z$-axis direction. The induced emf,during the passage of these loops out of the field region,will not remain constant for:

$A$ coil of mean area $500 \ cm^2$ and having $1000$ turns is held with its plane perpendicular to a uniform magnetic field of $0.4 \ G$. If the coil is turned through $180^{\circ}$ in $\frac{1}{10} \ s$,then the average induced emf is $(1 \ G = 10^{-4} \ T)$. (in $V$)