$A$ conducting wheel with four rods of length $l$,as shown in the figure,is rotating with angular velocity $\omega$ in a uniform magnetic field $B$. The induced potential difference between its center and rim will be

  • A
    $2B\omega l^2$
  • B
    $\sqrt{Bl^2\omega}$
  • C
    $\frac{Bl\omega}{2}$
  • D
    $\frac{Bl^2\omega}{2}$

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Find out $V_A - V_B = ?$

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