A conducting wire frame is placed in a magnet | vedclass

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(A) The magnetic field is directed into the paper and is increasing with time. According to Lenz's law,the induced current will create a magnetic fiel

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$B$ to $A$ and $D$ to $C$

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(A) The magnetic field is directed into the paper and is increasing with time. According to Lenz's law,the induced current will create a magnetic field that opposes this increase,meaning the induced magnetic field must be directed out of the paper. For the loops to produce an outward magnetic field,the induced current must flow in an anticlockwise direction in both loops. The induced electromotive force (emf) is given by $e = -\frac{d\phi}{dt} = -A \cdot \frac{dB}{dt}$. Since the area $A$ of the right-side loop is larger than the area of the left-side loop,the induced emf in the right-side loop is greater. Consequently,the net current in the entire circuit will be dominated by the anticlockwise flow in the larger loop. Following the anticlockwise path in the larger loop,the current flows from $D$ to $C$. Following the anticlockwise path in the smaller loop,the current flows from $B$ to $A$. Therefore,the direction of current is $B$ to $A$ and $D$ to $C$. Thus,option $(A)$ is correct.

$A$ conducting wire frame is placed in a magnetic field which is directed into the paper. The magnetic field is increasing at a constant rate. The directions of induced current in wires $AB$ and $CD$ are

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