$A$ cricket ball is thrown up with a speed of $19.6 \ m/s$. The maximum height it can reach is ......... $m$.

$A$ body is thrown vertically upwards with a velocity $u$. Find the true statement from the following:

$A$ ball is dropped from a bridge $122.5\, m$ above a river. After the ball has been falling for $2\, s$,a second ball is thrown straight down after it. What must its initial velocity be so that both hit the water at the same time?.......$m/s$

$A$ ball is thrown vertically upwards with a speed of $10 \ m/s$ from the top of a tower $200 \ m$ high and another is thrown vertically downwards with the same speed simultaneously. The time difference between them in reaching the ground (in $s$) is: $(g = 10 \ m/s^2)$

$A$ body falling from a vertical height of $10 \, m$ pierces through a distance of $1 \, m$ in sand. It faces an average retardation in sand equal to (where $g$ = acceleration due to gravity).

$A$ ball is released from the top of a tower of height $h$ meters. It takes $T$ seconds to reach the ground. What is the position of the ball in $\frac{T}{3}$ seconds?