$A$ cricket ball of mass $250\, g$ collides with a bat with velocity $10\, m/s$ and returns with the same velocity within $0.01\, s$. The force exerted on the ball is ....... $N$.

$A$ body of mass $5 \, kg$ is moving with a momentum of $10 \, kg \cdot m/s$. $A$ force of $0.2 \, N$ acts on it in the direction of motion of the body for $10 \, seconds$. The increase in its kinetic energy is ............... $J$.

$A$ cannon after firing recoils due to

$A$ soccer ball of mass $250 \text{ g}$ is moving horizontally to the left with a speed $22 \text{ ms}^{-1}$. This ball is kicked towards the right with a velocity $30 \text{ ms}^{-1}$ at an angle $53^{\circ}$ with the horizontal in the upward direction. Assuming that it took $0.01 \text{ s}$ for the collision to take place, the average force acting is $(\cos 53^{\circ} = \frac{3}{5}; \sin 53^{\circ} = \frac{4}{5})$. (in $\text{ N}$)

"Momentum is the product of velocity and its magnitude." Is this statement true or false?

$A$ body of mass $50 \, g$ has a velocity of $20 \, cm/s$. If a constant force of $50 \, dyne$ acts on it,what will be its momentum after $5 \, s$?