(B) According to the Work-Energy Theorem,the work done by the force $F$ on the ball is equal to the change in its kinetic energy,which is equal to the

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(B) According to the Work-Energy Theorem,the work done by the force $F$ on the ball is equal to the change in its kinetic energy,which is equal to the potential energy gained at the maximum height.Work done by the machine,$W = F \times S$,where $S = 0.2 \, m$.Potential energy gained at maximum height,$U = mgh$,where $m = 0.15 \, kg$,$g = 10 \, m/s^2$,and $h = 20 \, m$.Equating the work done to the potential energy: $F \times S = mgh$.$F \times 0.2 = 0.15 \times 10 \times 20$.$F \times 0.2 = 30$.$F = \frac{30}{0.2} = 150 \, N$.

Class 11 Physics Work, Energy and Power Work Energy Theorem and Conservation of Mechanical Energy

Medium

$A$ cricket ball of mass $0.15 \, kg$ is thrown vertically up by a bowling machine so that it rises to a maximum height of $20 \, m$ after leaving the machine. If the part pushing the ball applies a constant force $F$ on the ball and moves a distance of $0.2 \, m$ while launching the ball,the value of $F$ (in $N$) is $(g = 10 \, m/s^2)$.

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$200$
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$150$
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$275$
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$325$

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Work, Energy and Power

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Work Energy Theorem and Conservation of Mechanical Energy

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$A$ body of mass $1 \text{ kg}$ moves along a straight line with a velocity $v = 2x^2$. The work done by the body during displacement from $x = 0$ to $5 \text{ m}$ is . . . . . . $J$.

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