$A$ cricket player catches a ball of mass $120 \,g$ moving with $25 \,m/s$ speed. If the catching process is completed in $0.1 \,s$, then the magnitude of force exerted by the ball on the hand of the player will be (in $SI$ unit):

An object of mass $2 \, kg$ is placed at rest in a frame $S_1$ moving with velocity $10 \hat{i} + 5 \hat{j} \, m/s$ and having acceleration $5 \hat{i} + 10 \hat{j} \, m/s^2$. The object is also seen by an observer standing in a frame $S_2$ moving with velocity $5 \hat{i} + 10 \hat{j} \, m/s$. Calculate the net force acting on the object with respect to the $S_1$ frame.

$A$ body of mass $5 \; kg$ is acted upon by two perpendicular forces $8 \; N$ and $6 \; N$. Find the magnitude and direction of the acceleration of the body.

The ratio of the change in linear momentum to the time taken for this change represents which physical quantity?

$A$ force on an object of mass $100\, g$ is $(10 \hat{i}+5 \hat{j})\ N$. The position of that object at $t= 2\ s$ is $(a \hat{i}+b \hat{j})\, m$ after starting from rest. The value of $\frac{a}{b}$ will be..........

$A$ body,under the action of a force $\vec F = 6\hat i - 8\hat j + 10\hat k$,acquires an acceleration of $1\, m/s^2$. The mass of this body must be