$A$ cube of aluminium of sides $0.1 \, m$ is subjected to a shearing force of $100 \, N$. The top face of the cube is displaced through $0.02 \, cm$ with respect to the bottom face. The shearing strain would be

  • A
    $0.02$
  • B
    $0.1$
  • C
    $0.005$
  • D
    $0.002$

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