A cubic metre of silver weighing 900, Kg is r | vedclass

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Question

(A) Let $x$ be the side of the square cross-section of the $16\, m$ long bar.Since the volume of the silver is $1\, m^3$,we have $16 	imes x^2 = 1\,

Vedclass · Accepted Answer

$14\, Kg\, 62\frac{1}{2}\, g$

Vedclass · Answer

(A) Let $x$ be the side of the square cross-section of the $16\, m$ long bar.Since the volume of the silver is $1\, m^3$,we have $16 	imes x^2 = 1\, m^3$.Thus,$x^2 = \frac{1}{16}$,which gives $x = \frac{1}{4}\, m$.An exact cube cut from this bar will have a side length equal to the side of the square cross-section,which is $x = \frac{1}{4}\, m$.The volume of this cube is $V = x^3 = (\frac{1}{4})^3 = \frac{1}{64}\, m^3$.Given that $1\, m^3$ of silver weighs $900\, Kg$,the weight of the cube is $\frac{900}{64}\, Kg$.Calculating this: $\frac{900}{64} = 14.0625\, Kg$.$14.0625\, Kg = 14\, Kg + 0.0625 	imes 1000\, g = 14\, Kg\, 62.5\, g$ or $14\, Kg\, 62\frac{1}{2}\, g$.

$A$ cubic metre of silver weighing $900\, Kg$ is rolled into a $16\, m$ long square bar. Find out the weight of an exact cube cut off from it.

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