A current of 1, A is drawn by a filament of a | vedclass

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(D) The formula for electric current is $I = Q / t$,where $I$ is the current,$Q$ is the total charge,and $t$ is the time.Given $I = 1\, A$ and $t = 16

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$10^{20}$

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(D) The formula for electric current is $I = Q / t$,where $I$ is the current,$Q$ is the total charge,and $t$ is the time.Given $I = 1\, A$ and $t = 16\, s$,the total charge $Q = I 	imes t = 1\, A 	imes 16\, s = 16\, C$.The charge of a single electron is $e = 1.6 	imes 10^{-19}\, C$.The number of electrons $n$ is given by the formula $Q = n 	imes e$,which implies $n = Q / e$.Substituting the values: $n = 16 / (1.6 	imes 10^{-19}) = 10 / 10^{-19} = 10^{20}$.Therefore,the number of electrons passing through the filament is $10^{20}$.

$A$ current of $1\, A$ is drawn by a filament of an electric bulb. The number of electrons passing through a cross-section of the filament in $16$ seconds would be roughly:

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