A current of 0.01 A is passed through a solu | vedclass

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(C) According to Faraday's first law of electrolysis,the mass of substance deposited is given by $w = \frac{I 	imes t 	imes M_{wt}}{n 	imes F}$.Her

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) According to Faraday's first law of electrolysis,the mass of substance deposited is given by $w = \frac{I 	imes t 	imes M_{wt}}{n 	imes F}$.Here,$I = 0.01 \ A$,$t = 3 \ hours = 3 	imes 3600 \ s = 10800 \ s$,$w = 0.072 \ g$,$M_{wt} = 192 \ g/mol$,and $n = x$.Substituting the values: $0.072 = \frac{0.01 	imes 10800 	imes 192}{x 	imes 96500}$.$0.072 = \frac{108 	imes 192}{x 	imes 96500}$.$x = \frac{108 	imes 192}{0.072 	imes 96500}$.$x = \frac{20736}{6948} \approx 2.98$.Thus,the value of $x$ is approximately $3$.

$A$ current of $0.01 \ A$ is passed through a solution of a metal bromide $(MBr_x)$. The only reaction at the cathode is the deposition of metal $(M)$. After $3 \ hours$,$0.072 \ g$ of metal $(M)$ is deposited. The value of '$x$' is approximately (Given: Atomic weight of $M = 192$)

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