A cyclic process on an ideal monatomic gas is | vedclass

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(B) For a cyclic process,the change in internal energy $\Delta U = 0$.According to the first law of thermodynamics,$Q = \Delta U + W$. Since $\Delta U

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Net heat energy has been supplied to the system.

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(B) For a cyclic process,the change in internal energy $\Delta U = 0$.According to the first law of thermodynamics,$Q = \Delta U + W$. Since $\Delta U = 0$,we have $Q = W$.The work done in a cyclic process is equal to the area enclosed by the $PV$ diagram.Since the cycle is traced in a clockwise direction,the net work done $W$ by the gas is positive $(W > 0)$.Therefore,the net heat energy $Q$ supplied to the system must be positive $(Q > 0)$,meaning heat is supplied to the system.Thus,option $(b)$ is correct.

$A$. Steam engine	$I$. Magnetic confinement of plasma
$B$. Electron microscope	$II$. Laws of thermodynamics
$C$. Non-reflecting coatings	$III$. Wave nature of electrons
$D$. Tokamak	$IV$. Interference of light

$A$ cyclic process on an ideal monatomic gas is shown in the figure. The correct statement is:

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