A cylinder of 5 , L capacity,filled with air | vedclass

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Question

(A) Given that the initial pressure at $NTP$ is $P_1 = 76 \, cm$ of $Hg$.Initial volume $V_1 = 5 \, L$.The total final volume after connecting the two

Vedclass · Accepted Answer

$10.8$

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(A) Given that the initial pressure at $NTP$ is $P_1 = 76 \, cm$ of $Hg$.Initial volume $V_1 = 5 \, L$.The total final volume after connecting the two cylinders is $V_2 = 5 \, L + 30 \, L = 35 \, L$.According to Boyle's law,at constant temperature,$P_1V_1 = P_2V_2$.Substituting the values: $76 	imes 5 = P_2 	imes 35$.$P_2 = \frac{76 	imes 5}{35} = \frac{380}{35} \approx 10.857 \, cm$ of $Hg$.Rounding to the nearest option,the result is $10.8 \, cm$ of $Hg$.

$A$ cylinder of $5 \, L$ capacity,filled with air at $NTP$,is connected to another evacuated cylinder of $30 \, L$ capacity. The resultant air pressure in both the cylinders will be .............. $cm$ of $Hg$.

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