A cylinder with a movable piston contains 3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The process is adiabatic because the cylinder walls and the piston are heat insulators.For an adiabatic process,the relation between pressure and

Vedclass · Accepted Answer

$(2)^{7/5}$

Vedclass · Answer

(A) The process is adiabatic because the cylinder walls and the piston are heat insulators.For an adiabatic process,the relation between pressure and volume is given by $P_1 V_1^\gamma = P_2 V_2^\gamma$.Here,$V_2 = \frac{V_1}{2}$,so $\frac{V_1}{V_2} = 2$.For hydrogen (a diatomic gas),the adiabatic index is $\gamma = \frac{C_p}{C_v} = \frac{7/2 R}{5/2 R} = \frac{7}{5}$.Substituting these values into the adiabatic equation:$\frac{P_2}{P_1} = \left( \frac{V_1}{V_2} \right)^\gamma = (2)^{7/5}$.Thus,the pressure increases by a factor of $(2)^{7/5}$.

Similar Questions

An ideal gas,undergoing adiabatic change,has which of the following pressure-temperature relationships?

Specific heat of a gas undergoing adiabatic change is

The amount of work done in an adiabatic expansion from temperature $T$ to ${T_1}$ is

For an adiabatic compression of $1 \text{ kmol}$ of gas,$146 \text{ kJ}$ of work is done. During this process,the temperature of the gas increases by $7 \text{ °C}$. The gas is ........

$A$ litre of dry air at $STP$ expands adiabatically to a volume of $3$ litres. If $\gamma=1.40,$ the work done by air is $(3^{1.4}=4.6555)$. [Take air to be an ideal gas] (in $; J$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module