$A$ diatomic gas $(\gamma = 1.4)$ does $200 \,J$ of work when it is expanded isobarically. The heat given to the gas in the process is: (in $\,J$)

One mole of an ideal gas is contained within a cylinder by a frictionless piston and is initially at temperature $T$. The pressure of the gas is kept constant while it is heated and its volume doubles. If $R$ is the molar gas constant,the work done by the gas in increasing its volume is

$10 \text{ mole}$ of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from $P_1$ to $P_2$ at constant volume $V = 1 \text{ m}^3$ is $\alpha \text{ Joule}$ ($P_1 = 21.7 \text{ Pa}$, $P_2 = 30 \text{ Pa}$, $C_v = 21 \text{ J/K} \cdot \text{mol}$, $R = 8.3 \text{ J/mol} \cdot \text{K}$). The value of $\alpha$ is . . . . . . .

If $\gamma$ is the ratio of molar specific heat at constant pressure to molar specific heat at constant volume for a gas,find the change in internal energy of $1 \, mol$ of the gas when its volume changes from $V$ to $2V$ at constant pressure $P$.

The ratio of work done by an ideal rigid diatomic gas to the heat supplied to the gas in an isobaric process is (in $/7$)

$A$ cyclic process of a thermodynamic system is taken through $a \to b \to c \to d \to a$ as shown in the $P-V$ diagram. The work done by the gas along the path $b \to c$ is