A diatomic gas with rigid molecules does 10 | vedclass

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(C) For a diatomic gas with rigid molecules,the molar heat capacity at constant pressure is given by $C_{p} = \frac{7}{2} R$.The work done in an isoba

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$35$

Vedclass · Answer

(C) For a diatomic gas with rigid molecules,the molar heat capacity at constant pressure is given by $C_{p} = \frac{7}{2} R$.The work done in an isobaric process is given by $W = P \Delta V = nR \Delta T = 10 \ J$.The heat energy absorbed by the gas is given by $\Delta Q = n C_{p} \Delta T$.Substituting $C_{p} = \frac{7}{2} R$,we get $\Delta Q = n \left( \frac{7}{2} R ight) \Delta T = \frac{7}{2} (nR \Delta T)$.Since $nR \Delta T = W = 10 \ J$,we have $\Delta Q = \frac{7}{2} 	imes 10 \ J = 35 \ J$.

$A$ diatomic gas with rigid molecules does $10 \ J$ of work when expanded at constant pressure. What would be the heat energy absorbed by the gas,in this process ..... $J$.

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