A diode having a potential difference of 0.5, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The diode and the resistor are connected in series with the voltage source.According to Kirchhoff's voltage law,the source voltage $V_s$ is the su

Vedclass · Accepted Answer

$2.5$

Vedclass · Answer

(C) The diode and the resistor are connected in series with the voltage source.According to Kirchhoff's voltage law,the source voltage $V_s$ is the sum of the potential difference across the diode $(V_d)$ and the potential difference across the resistor $(V_r)$.Given:Potential difference across the diode,$V_d = 0.5\,V$Resistance,$R = 20\,\Omega$Current in the circuit,$I = 0.1\,A$The potential difference across the resistor is $V_r = I 	imes R = 0.1\,A 	imes 20\,\Omega = 2\,V$.Therefore,the source voltage is $V_s = V_d + V_r = 0.5\,V + 2\,V = 2.5\,V$.

$A$ diode having a potential difference of $0.5\,V$ across its junction,which does not depend on the current,is connected in series with a resistance of $20\,\Omega$ across a source. If $0.1\,A$ current passes through the resistance,what is the voltage of the source (in $,V$)?

Similar Questions

The work done by a force $\vec F = (-6x^3 \hat i) \, N$,in displacing a particle from $x = 4 \, m$ to $x = -2 \, m$ is ................ $J$.

Gas is being pumped into a spherical balloon at the rate of $30 \ ft^3 / min$. The rate at which the radius increases when it reaches the value $15 \ ft$, is:

The most appropriate magnetization $M$ versus magnetising field $H$ curve for a paramagnetic substance is

If $\frac{x^2}{a} + \frac{2xy}{h} + \frac{y^2}{b} = 0$ represents a pair of straight lines such that the slope of one of the lines is twice the other,then $\frac{ab}{h^2} =$

Which of the following is not a colligative property?

Vedclass Test Series

Exam Paper Generator

Online Exam Module