A diver at a depth of 12 m in water (mu = 4/ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When a diver looks up from inside the water,the light from the sky enters the water and undergoes refraction. Due to the phenomenon of total inter

Vedclass · Accepted Answer

$\sin^{-1}(3/4)$

Vedclass · Answer

(C) When a diver looks up from inside the water,the light from the sky enters the water and undergoes refraction. Due to the phenomenon of total internal reflection,the diver sees the sky within a cone of light.The semi-vertical angle of this cone is equal to the critical angle $(C)$ for the water-air interface.The formula for the critical angle is given by $\sin(C) = \frac{1}{\mu}$,where $\mu$ is the refractive index of water with respect to air.Given $\mu = 4/3$,we have $\sin(C) = \frac{1}{4/3} = \frac{3}{4}$.Therefore,the semi-vertical angle is $C = \sin^{-1}(3/4)$.

$A$ diver at a depth of $12 \ m$ in water $(\mu = 4/3)$ sees the sky in a cone of semi-vertical angle:

Similar Questions

With respect to air,the critical angle in a medium for light of red colour $[{\lambda _1}]$ is $\theta$. Other factors remaining the same,the critical angle for light of yellow colour $[{\lambda _2}]$ will be:

The velocity of light in a medium is half its velocity in air. If a ray of light emerges from such a medium into air,the angle of incidence,at which it will be totally internally reflected,is ......... $^o$

In total internal reflection,when the angle of incidence is equal to the critical angle for the pair of media in contact,what will be the angle of refraction in degrees?

The phenomenon by which light travels in an optical fibre is

$A$ diver at a depth of $12 \ m$ in water $\left(\mu = \frac{4}{3}\right)$ sees the sky in a cone of semi-vertical angle:

Vedclass Test Series

Exam Paper Generator

Online Exam Module