A diverging lens of focal length 10 , cm is p | vedclass

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Question

(A) $1$. For a diverging lens,the focal length $f = -10 \, cm$. Since the light comes from a very far away source,the object distance $u = \infty$.$2$

Vedclass · Accepted Answer

$20 \, cm$ behind the mirror

Vedclass · Answer

(A) $1$. For a diverging lens,the focal length $f = -10 \, cm$. Since the light comes from a very far away source,the object distance $u = \infty$.$2$. Using the lens formula $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$,we get $\frac{1}{v} - \frac{1}{\infty} = \frac{1}{-10}$,which gives $v = -10 \, cm$. This means the first image $I_1$ is formed $10 \, cm$ in front of the lens.$3$. The distance between the lens and the mirror is $10 \, cm$. Since $I_1$ is $10 \, cm$ in front of the lens,it is $10 + 10 = 20 \, cm$ in front of the mirror.$4$. The plane mirror forms an image of $I_1$ at the same distance behind the mirror. Thus,the final image $I_2$ is formed $20 \, cm$ behind the mirror.

$A$ diverging lens of focal length $10 \, cm$ is placed $10 \, cm$ in front of a plane mirror as shown in the figure. Light from a very far away source falls on the lens. The final image is at a distance

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