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(B) The angular position $	heta$ of the $n^{th}$ bright fringe in a Young's double slit experiment is given by the formula: $	heta = \frac{n\lambda}

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$6 	imes 10^{-3}\,rad$

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(B) The angular position $	heta$ of the $n^{th}$ bright fringe in a Young's double slit experiment is given by the formula: $	heta = \frac{n\lambda}{d}$.Given values are:$n = 10$$\lambda = 6000\,\mathring{A} = 6000 	imes 10^{-10}\,m = 6 	imes 10^{-7}\,m$$d = 0.1\,cm = 10^{-3}\,m$Substituting these values into the formula:$	heta = \frac{10 	imes 6 	imes 10^{-7}}{10^{-3}}$$	heta = 60 	imes 10^{-4}\,rad = 6 	imes 10^{-3}\,rad$.

$A$ double slit experiment is performed by using light of wavelength $6000\,\mathring{A}$. If the distance of the screen is $1\,m$ and the slits are $0.1\,cm$ apart,then calculate the angular position of the $10^{th}$ bright fringe.

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