$A$ fair die is thrown up to $20$ times. The probability that on the $10^{th}$ throw,the fourth six appears is:

  • A
    $\frac{84 \times 5^6}{6^{10}}$
  • B
    $\frac{112 \times 5^6}{6^{10}}$
  • C
    $\frac{84 \times 5^6}{6^{20}}$
  • D
    None

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