$A$ father's age is three times the sum of the ages of his two children,but $20 \, \text{years}$ hence his age will be equal to the sum of their ages. Then,the father's age is (in $\text{years}$)

$A$ father is now $3$ times as old as his son. $5$ years back,he was $4$ times as old as his son. The age of the son is:

In a family,mother's age is twice that of daughter's age. Father is $10 \,years$ older than mother. Brother is $20 \,years$ younger than his mother and $5 \,years$ older than his sister. What is the age of the father? (in $years$)

The sum of the ages of $4$ members of a family,$5$ $years$ ago,was $94$ $years$. Today,when the daughter has been married off and replaced by a daughter-in-law,the sum of their ages is $92$ $years$. Assuming that there has been no other change in the family structure and all the people are alive,what is the difference between the age of the daughter and that of the daughter-in-law? (in $years$)

The present age of Romila is $\frac{1}{4}$ that of her father. After $6\, \text{years}$, her father's age will be twice the age of Kapil. If Kapil celebrated his fifth birthday $8\, \text{years}$ ago, what is Romila's present age? (in $\text{years}$)

The sum of the ages of two brothers, having a difference of $8 \, \text{years}$ between them, will double after $10 \, \text{years}$. What is the ratio of the age of the younger brother to that of the elder brother?