A faulty thermometer has its fixed points mar | vedclass

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Question

(C) Let $T_{C}$ be the correct temperature on the Celsius scale.The formula relating a faulty scale to the Celsius scale is given by:$\frac{T_{C} - 0}

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(C) Let $T_{C}$ be the correct temperature on the Celsius scale.The formula relating a faulty scale to the Celsius scale is given by:$\frac{T_{C} - 0}{100 - 0} = \frac{X - X_{L}}{X_{U} - X_{L}}$Where:$X = 59^{\circ}$ (reading on the faulty thermometer)$X_{L} = 5^{\circ}$ (lower fixed point)$X_{U} = 95^{\circ}$ (upper fixed point)Substituting the values:$\frac{T_{C}}{100} = \frac{59 - 5}{95 - 5}$$\frac{T_{C}}{100} = \frac{54}{90}$$\frac{T_{C}}{100} = \frac{6}{10} = 0.6$$T_{C} = 0.6 	imes 100 = 60^{\circ}$

$A$ faulty thermometer has its fixed points marked $5^{\circ}$ and $95^{\circ}$. This thermometer reads the temperature of a body as $59^{\circ}$. Then the correct temperature of the body on the Celsius scale is ........ $^{\circ}$.

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