A finite ladder is constructed by connecting | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For the equivalent capacitance to be independent of the number of sections,the ladder must behave as an infinite ladder. Let the equivalent capaci

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(A) For the equivalent capacitance to be independent of the number of sections,the ladder must behave as an infinite ladder. Let the equivalent capacitance between points $A$ and $B$ be $C_{eq} = C$.If we add one more section to the infinite ladder,the equivalent capacitance remains $C$. The circuit consists of a $2\,\mu F$ capacitor in parallel with the series combination of a $4\,\mu F$ capacitor and the rest of the infinite ladder (which also has an equivalent capacitance $C$).Thus,the equation is:$C = 2 + \frac{4 	imes C}{4 + C}$Multiplying by $(4 + C)$:$C(4 + C) = 2(4 + C) + 4C$$C^2 + 4C = 8 + 2C + 4C$$C^2 - 2C - 8 = 0$Solving the quadratic equation:$(C - 4)(C + 2) = 0$Since capacitance cannot be negative,we have $C = 4\,\mu F$.

Similar Questions

$A$ convex lens $A$ of focal length $20 \ cm$ and a concave lens $B$ of focal length $5 \ cm$ are kept along the same axis with a distance $d$ between them. If a parallel beam of light falling on $A$ leaves $B$ as a parallel beam,then the distance $d$ in $cm$ will be

The effect due to a uniform magnetic field on a freely suspended magnetic needle is as follows:

The transition from the state $n=3$ to $n=1$ in a hydrogen-like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition from:

Two capacitors $C_1$ and $C_2$ in a circuit are joined as shown in the figure. The potential of point $A$ is $V_1$ and that of $B$ is $V_2$. The potential of point $D$ will be

$A$ choke coil works on the principle of

Vedclass Test Series

Exam Paper Generator

Online Exam Module