A first order reaction has the rate constant | vedclass

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(C) For a first order reaction,the concentration at time $t$ is given by $[A]_t = [A]_0 e^{-kt}$.Given: $[A]_0 = 1 \ M$,$k = 10^{-2} \ sec^{-1}$,$t =

Vedclass · Accepted Answer

$5.5 	imes 10^{-3} \ mol \ L^{-1} \ sec^{-1}$

Vedclass · Answer

(C) For a first order reaction,the concentration at time $t$ is given by $[A]_t = [A]_0 e^{-kt}$.Given: $[A]_0 = 1 \ M$,$k = 10^{-2} \ sec^{-1}$,$t = 1 \ minute = 60 \ sec$.$[A]_t = 1 	imes e^{-(10^{-2} 	imes 60)} = e^{-0.6}$.Using $e^{-0.6} \approx 0.5488 \ M$.The rate of reaction at time $t$ is $Rate = k[A]_t$.$Rate = 10^{-2} \ sec^{-1} 	imes 0.5488 \ M = 5.488 	imes 10^{-3} \ mol \ L^{-1} \ sec^{-1} \approx 5.5 	imes 10^{-3} \ mol \ L^{-1} \ sec^{-1}$.

$A$ first order reaction has the rate constant $10^{-2} \ sec^{-1}$. If the initial concentration of reactant is $1 \ M$,then what will be the rate of reaction after $1 \ minute$?

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