A fixed mass 'm' of a gas is subjected to a t | vedclass

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(B) $1.$ In the $P-V$ diagram:$K \rightarrow L$: Constant pressure $(P)$,volume $(V)$ increases. By Charles's Law $(V \propto T)$,$T$ increases (Heati

Vedclass · Accepted Answer

$(C, B)$

Vedclass · Answer

(B) $1.$ In the $P-V$ diagram:$K \rightarrow L$: Constant pressure $(P)$,volume $(V)$ increases. By Charles's Law $(V \propto T)$,$T$ increases (Heating).$L \rightarrow M$: Constant volume $(V)$,pressure $(P)$ decreases. By Gay-Lussac's Law $(P \propto T)$,$T$ decreases (Cooling).$M \rightarrow N$: Constant pressure $(P)$,volume $(V)$ decreases. By Charles's Law,$T$ decreases (Cooling).$N \rightarrow K$: Constant volume $(V)$,pressure $(P)$ increases. By Gay-Lussac's Law,$T$ increases (Heating).Thus,the sequence is Heating,Cooling,Cooling,Heating,which corresponds to option $(C)$.$2.$ An isochoric process is one where volume remains constant. In the diagram,the vertical lines represent constant volume processes.These are $L \rightarrow M$ and $N \rightarrow K$. This corresponds to option $(B)$.Therefore,the correct answer is $(C, B)$.

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