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(B) The average intensity $I_{av}$ of an electromagnetic wave is given by the formula:$I_{av} = \frac{1}{2} c \epsilon_0 E_0^2$Given:$E_0 = 36 \, V/m$

Vedclass · Accepted Answer

$1.72$

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(B) The average intensity $I_{av}$ of an electromagnetic wave is given by the formula:$I_{av} = \frac{1}{2} c \epsilon_0 E_0^2$Given:$E_0 = 36 \, V/m$$c = 3 	imes 10^8 \, m/s$$\epsilon_0 = 8.85 	imes 10^{-12} \, C^2/(N \cdot m^2)$Substituting the values:$I_{av} = \frac{1}{2} 	imes (3 	imes 10^8) 	imes (8.85 	imes 10^{-12}) 	imes (36)^2$$I_{av} = 0.5 	imes 3 	imes 10^8 	imes 8.85 	imes 10^{-12} 	imes 1296$$I_{av} = 1.5 	imes 8.85 	imes 1296 	imes 10^{-4}$$I_{av} = 17208.6 	imes 10^{-4} \approx 1.72 \, W/m^2$

$A$ flood light is covered with a filter that transmits red light. The electric field of the emerging beam is represented by a sinusoidal plane wave
$E_x=36\,\sin\,(1.20 \times 10^7z -3.6 \times 10^{15}\,t)\,V/m$
The average intensity of the beam will be.....$W/m^2$

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$A$ flood light is covered with a filter that transmits red light. The electric field of the emerging beam is represented by a sinusoidal plane wave$E_x=36\,\sin\,(1.20 \times 10^7z -3.6 \times 10^{15}\,t)\,V/m$The average intensity of the beam will be.....$W/m^2$