A force vec{F}=(3 hat{i}+4 hat{j}) ;N acts on | vedclass

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(D) The force $\vec{F}$ is a constant force given by $\vec{F} = (3 \hat{i} + 4 \hat{j}) \;N$.The particle moves from the origin $(0,0) \;m$ to $(4,0)

Vedclass · Accepted Answer

$+24$

Vedclass · Answer

(D) The force $\vec{F}$ is a constant force given by $\vec{F} = (3 \hat{i} + 4 \hat{j}) \;N$.The particle moves from the origin $(0,0) \;m$ to $(4,0) \;m$ and then to $(4,3) \;m$. The total displacement vector $\vec{d}$ is the vector from the initial position $(0,0)$ to the final position $(4,3)$,which is $\vec{d} = (4 \hat{i} + 3 \hat{j}) \;m$.Since the force is constant,the work done $W$ is given by the dot product of the force and the displacement vector:$W = \vec{F} \cdot \vec{d}$$W = (3 \hat{i} + 4 \hat{j}) \cdot (4 \hat{i} + 3 \hat{j})$$W = (3 	imes 4) + (4 	imes 3)$$W = 12 + 12 = 24 \;J$.Therefore,the total work done is $24 \;J$.

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