$A$ galvanometer of $10 \,\Omega$ resistance gives full scale deflection with $0.01 \, A$ of current. It is to be converted into an ammeter for measuring $10 \, A$ current. The value of shunt resistance required will be

  • A
    $\frac{10}{999} \,\Omega$
  • B
    $0.1 \,\Omega$
  • C
    $0.5 \,\Omega$
  • D
    $1.0 \,\Omega$

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Similar Questions

Consider two identical galvanometers and two identical resistors with resistance $R$. If the internal resistance of the galvanometers is $R_G < R/2$,which of the following configurations yield the maximum voltage range and maximum current range?

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$A$ galvanometer coil of resistance $50 \,\Omega$ shows full-scale deflection for a current of $100 \,\mu A$. The shunt resistance to be added to the galvanometer to convert it into an ammeter of range $10 \, mA$ is:

$A$ galvanometer coil has a resistance of $15\; \Omega$ and the meter shows full-scale deflection for a current of $4\; mA$. How will you convert the meter into an ammeter of range $0$ to $6\; A$?

$A$ moving coil galvanometer has $50$ turns and each turn has an area $2 \times 10^{-4} \ m^2$. The magnetic field produced by the magnet inside the galvanometer is $0.02 \ T$. The torsional constant of the suspension wire is $10^{-4} \ N \ m \ rad^{-1}$. When a current flows through the galvanometer,a full-scale deflection occurs if the coil rotates by $0.2 \ rad$. The resistance of the coil of the galvanometer is $50 \ \Omega$. This galvanometer is to be converted into an ammeter capable of measuring current in the range $0-1.0 \ A$. For this purpose,a shunt resistance is to be added in parallel to the galvanometer. The value of this shunt resistance,in ohms,is:

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