Class 12PhysicsMoving Charges and MagnetismThe Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion
Medium$A$ galvanometer of $50 \, \Omega$ resistance has $25$ divisions. $A$ current of $4 \times 10^{-4} \, A$ gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of $25 \, V$, it should be connected with a resistance of
- A$2500 \, \Omega$ as a shunt
- B$2450 \, \Omega$ as a shunt
- C$2550 \, \Omega$ in series
- D$2450 \, \Omega$ in series
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Similar Questions
$A$ shunt of resistance $1\,\Omega$ is connected across a galvanometer of $120\,\Omega$ resistance. $A$ total current of $5.5\,A$ is passed through the combination,which gives full-scale deflection in the galvanometer. The current that would give full-scale deflection in the absence of the shunt is nearly ............... $A$.
$A$ milliammeter of range $10\, mA$ and resistance $9\, \Omega$ is joined in a circuit as shown. The meter gives full-scale deflection for current $I$ when $A$ and $B$ are used as its terminals,i.e.,current enters at $A$ and leaves at $B$ ($C$ is left isolated). The value of $I$ is
Medium
View SolutionIn a circuit,$5$ percent of the total current passes through a galvanometer. If the resistance of the galvanometer is $G$,then the value of the shunt is:
Medium
View SolutionMatch the terms given in List-$I$ with suitable options provided in List-$II$ regarding the experiment to calculate the resistance and figure of merit of a galvanometer using the half-deflection method:
List-$I$ List-$II$ $A$. Figure of merit $(k)$ $P$. in series $B$. Current sensitivity $(SI)$ $Q$. to get power loss minimized $C$. Deflection is made half by using low resistance $R$. in shunt/parallel $D$. High resistance box $S$. current per unit deflection $T$. deflection per unit current
| List-$I$ | List-$II$ |
|---|---|
| $A$. Figure of merit $(k)$ | $P$. in series |
| $B$. Current sensitivity $(SI)$ | $Q$. to get power loss minimized |
| $C$. Deflection is made half by using low resistance | $R$. in shunt/parallel |
| $D$. High resistance box | $S$. current per unit deflection |
| $T$. deflection per unit current |
Medium
View SolutionIn the circuit diagrams ($A, B, C$ and $D$) shown below,$R$ is a high resistance and $S$ is a resistance of the order of galvanometer resistance $G$. The correct circuit,corresponding to the half deflection method for finding the resistance and figure of merit of the galvanometer,is the circuit labelled as
DifficultJEE MAIN 2014
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